(1/4)^2x-1(64^-x)=1

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Solution for (1/4)^2x-1(64^-x)=1 equation: 



(1/4)^2x-1(64^-x)=1

We move all terms to the left:

(1/4)^2x-1(64^-x)-(1)=0



Domain of the equation: 4)^2x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+1/4)^2x-1(64^-x)-1=0

We multiply all the terms by the denominator


(+1-(1(64^-x))*4)^2x-1*4)^2x=0

Wy multiply elements

(+1-(1(64^-x))*4)^2x-4x=0

We add all the numbers together, and all the variables

-4x+(+1-(1(64^-x))*4)^2x=0

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